Syntes av AM-694 via Grignard-reaktion

William D.

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Steg 1:
8CyNU5m0HG

1. 4,00 g oxalylklorid tillsattes droppvis till en suspension av 1,00 g 2-jodbensoesyra i 30 ml diklormetan vid 0 *C.
2. Reaktionsblandningen värmdes upp till rumstemperatur och omrördes i 2 timmar.
3. Efter kylning avlägsnades lösningsmedlet och överskottet av oxalylklorid i vakuum för att ge en brun rest (0,90 g), som användes i nästa steg utan ytterligare rening.
4. 1,40 g indol i 5,0 ml eter tillsattes droppvis till en omrörd lösning av 3,17 ml 2,5 M etylmagnesiumbromid i eter, utspädd med 1,1 ml eter, vid 0 *C.
5. Lösningen omrördes i 0,5 h vid rumstemperatur och en lösning av 0,90 g 2-jodbenzoylklorid i 5 ml eter tillsattes droppvis.
6. Reaktionsblandningen omrördes i 1,5 h, kyldes med mättad vattenhaltig ammoniumklorid och omrördes tills det fasta ämnet hade brutits upp till en fin suspension.
7. Återstoden tvättades med vatten och eter och suspenderades sedan i 20 ml metanol, till vilken tillsattes 4 g natriumhydroxid och 10 ml vatten.
8. Blandningen omrördes vid rumstemperatur i 18 timmar, det fasta ämnet filtrerades bort och tvättades med successiva portioner av metanol, vatten och eter.
9. Torkning i vakuum vid 100 *C gav 1,06 g (70%) 3-(2-iodobenzoyl)indol som en viskös olja, vilken användes i nästa steg utan ytterligare rening.


Steg 2:
4RXODjV1Hx

1. 0,5 g natriumhydrat tillsattes till en lösning av 1,06 g 3-(2-jodbensoyl)indol i 10,0 ml N,N-dimetylformamid.
2. Reaktionsblandningen omrördes vid rumstemperatur och 1,03 g 1-brom-5-fluoropentan tillsattes långsamt.
3. Lösningen omrördes vid 120 *C under 1 h.
4. Efter kylning späddes reaktionsblandningen med vatten och extraherades med tre portioner etylacetat.
5. Extrakten tvättades med saltlösning och torkades, och lösningsmedlet avlägsnades i vakuum.
6. Utbyte 0,60 g (30 %) 1-(heptyl-7-karboxylat)-3-(2-iodobenzoyl)indol som ett gult fast ämne.
 
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Barter

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The synthesis says it makes 1-(heptyl-7-carboxylate)-3-(2-iodobenzoyl)indole, but it should be 1-(5-fluoropentyl)-3-(2-iodobenzoyl)indole (AM-694) based on 1-bromo-5-fluoropentane. No way that reagent adds a heptyl or carboxylate group. Looks like a mix-up—can you clarify the synthesis path?
Thanks
 

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I also have seen such misslabelings in chemicals that comed as synthetic canabinoids, on the image path all is clear but the think im seeing is the canabinoids that come from china was euphoric and strong, and now all this canabinoids made by this way or by kits are actualy less euphoric then thc, im almost shure here is a big lie that we normal people dont know, but from where comes the difference ?
 

HIGGS BOSSON

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If synthetic cannabinoid is weaker than THC, then it was synthesized with errors. The JWH series is much stronger than THC, maybe it's not always more euphoric, but many people like the powerful action of synthetics. Still, THC is milder.
 

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I remember when taking the first china adb-butinaca, 5f-sgt-151,am-2201, and some other i have tried from china and they were actualy so euphoric like third eye happines/euphoria 8/10 euphoria 8/10 sedation(thry were china stock but shiped from spain buyjwh if you remember them, and i tried the greece flyrc products first and was so disapointed, and recently tried a 5f i think, and that was not only not strong, but and making me feel so bad, normal thc is 5/10 euphoria and 3/10 sedation lets say for me when i dont have tolerance and all the newer ones made by the chinese precursors are so weak and i cant figure out why just zero euphoria, thats not how canabinoids are supposed to fell from my experience, i still havent tried to made a canabinoid but im a big enthusiast of FC or grignard so i must try haha
 
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@HIGGS BOSSON The synthesis claims to produce 1-(heptyl-7-carboxylate)-3-(2-iodobenzoyl)indole, but it should actually result in 1-(5-fluoropentyl)-3-(2-iodobenzoyl)indole (AM-694) using 1-bromo-5-fluoropentane. It's unlikely that this reagent would introduce a heptyl or carboxylate group. It seems like there might be a mix-up—could you clarify the synthesis route? Thank you!
 
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