Jauks un efektīvs ceļš pašsintēzes 2b4m sintēzei (vidēji 50 usd par kg)

[Dr. MMX]

Hey i ll tikai ierakstīt reaģentus, ko izmanto gudra izvēle (cena/ietilpība) aviable to buy in europe
Tātad 1.
PCL5 ar elementāro sēru > tionilhlorīds

tionilhlorīds + propionskābe > priopionilhlorīds

4mp sintēze (šeit ir tēma, tāpēc es varu pievienot tikai saiti):
Propionilhlorīds
Toluolsols
AlCl3 bezūdens

http://bbzzzsvqcrqtki6umym6itiixfhni37ybtt7mkbjyxn2pgllzxf2qgyd.onion/en/threads/synthesis-of-4-methylpropiophenone-from-toluene-by-friedel-crafts-reaction-1kg-scale.209/

dažaspplekan ir problēma to bromēt
sērskābe, kas nepieciešama, lai iegūtu Hbr, kas ir nedaudz dārga un nav bieži pieejama. Tā vietā mēs izmantojam:
Fosforskābi un NaBh reakcijai > iegūstam HBR.
H2O2 12 % var nopirkt un destilēt līdz vēl dažiem %, piemēram, 25-30 %.

Tātad
4 metilopropions + HBR + h2o2 > 2b4m

. Es neaprēķināju izmaksas, bet tās ir ļoti nelielas, un nav jāgaida sūtījums vai jābrīnās par zemas kvalitātes prekursoru.

 

[chost]

Vai varat sīkāk paskaidrot, kā izgatavot HBR?

 

[Dr. MMX]

Ak, es tiešām atvainojos, ka pieļāvu kļūdu. tā ir pareiza:
Lai no fosforskābes (H₃PO₄) un nātrija bromīda (NaBr) iegūtu bromskābi (HBr), var izmantot dubultās izspiešanas reakciju. Reakciju var attēlot šādi:

1. Reaktanti: Fosforskābe (H₃PO₄) un nātrija bromīds (NaBr).
2. Produkti: Bromskābe (HBr) un nātrija fosfāts (Na₃PO₄).

Reakcijas līdzsvarotais ķīmiskais vienādojums ir:


H3PO4+3NaBr→3HBr+Na3PO4


Šajā reakcijā fosforskābe reaģē ar nātrija bromīdu, iegūstot bromskābi un nātrija fosfātu.

 

[chost]

Vai ir nepieciešama destilācija?
Un cik lielā ūdens daudzumā vajadzētu izšķīdināt nātrija bromīdu?

 

[Dr. MMX]

Kā citādi jūs plānojat iegūt lietu, kas būtībā ir gāze?

Tas ir atkarīgs no tā, kādus % jūs vēlaties, maksimums ir 47%, cik es atceros, un tam vajadzētu būt jau šādā veidā.

 

[Benz88]

is it Safe to Distille the h2o2 to maybe 30-35% from 12%?

 

[TheVacuumGuy]

H3po4 ar NaBr, lai iegūtu HBr? Pēc brīža to izmēģināšu.

Ir daudz HBr, bet interesē, vai šie divi savienojumi reaģē.

 

[Dr. MMX]

jā un Na3PO4

 

[Dr. MMX]

Tas ir brīnišķīgi

 

[TheVacuumGuy]

Didn't work. I think it would be easier to add sulfuric acid to a solution of KBr (or NaBr) , which would readily yield HBr at 125c

 

[Dr. MMX]

I tried to override having sulfuric acid becasue here is troubles to get it. It was very extreme attempt
if there is access to sulfuric acid its easy job

 

[Dr. MMX]

you can get elemental bromine from potasium bromide, dont need to use acids.
it was quite cheap as i remember

 

[Toddler]

Hbr2 48% can work ?
(CAS.No: 10035-10-6)

how much ration use for bromination
Hbr2
H2O2
for 100g of 4MPP

 

[TheVacuumGuy]

Roughly,

H2o2 50ml
HBr 100ml

 

[Toddler]

for 100g of 4MPP

 

[w2x3f5]

Instead of propionyl chloride, can use propionic anhydride (obtain phosphorus oxide from propionic acid), can also use propionic acid directly with polyphosphoric acid (there are many options for this reaction, you can choose the best one). If propionyl chloride is used with anhydrous aluminum chloride (can be replaced with cheaper and simpler options). Then it is best to carry out a bromination reaction before hydrolysis in Fridel-Crafts (the complex of 2b4m and aluminum chloride is very active for bromination with a high yield).

 

[Dr. MMX]

In chemistry trade buissness in europe propionic acid is considered with "silent restriction" with reason it can be used as biological weapon, so should be avoided there.

very interesting choice of propionic anhydride

 

[Osmosis Vanderwaal]

@TheVacuumGuy you gave him bad figures and he used them and probably ruined 100G 2B4-MP. I dont know what he paid, but I got $200 all day for 10g if it's domestic . In th rules there are a few gold nuggets. "Use the fucking search engine." That's a rule. Another one is " a good chemist i an accurate chemist." Make sure that you clearly state you are guessing when you don't know. You could say nothing at all, you could show your math or you could tell him he needs to figure it himself, but please, dont just throw out random numbers, with no disclaimer.

 

[TheVacuumGuy]

Show me what's wrong then. I used these figures with success. note that hydrogen peroxide is a solution of 35%.

 

[TheVacuumGuy]

i stated roughly , not stoicimeticly

reactants	Coeff	Molar Mass	Moles (g/mol)	Weight (g)
C10H12O	1	148.20168	0,67	100
HBr	1	80.91194	0,67	54,595831842122166
H2O2	1	34.01468	0,67	22,951615663196257
products	1
C10H11BrO	1	227.09774	0.67	153,23560434672535
H2O	2	18.01528	1,35	24,311843158593074

HBr 48% = 8.77 mol/L => for required 0.67m corresponds to 0,0764L (76ml)
h2o2 35% = 11.63 mol/L => for required 0.67m corresponds to 0,0576L (57ml)

Yes that's a bit off from 100 and 50, but these numbers are theoretically, which almost never applies in practice. ( like a mephedrone synthesis is given methylamine x2 but theoretically only needs x1/5 )

furthermore excess reagents are neutralized afterwards.

 

[w2x3f5]

You have not taken into account the purity of precursors, at the end of the reaction you will not have acid. No acid = no protonation

 

[TheVacuumGuy]

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