G.Patton
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Theory.
Mephedrone can come in the form of capsules, tablets, crystals or white powder, that users may swallow, snort, inject, smoke or use rectally. The free base of mephedrone, obtained by a synthesis, is converted into a salt forms. Usually, they are performed as hydrochloric or hydrobromic salts of mephedrone. Both compounds are colorless to off-white powders or crystals after recrystallization from acetone. The melting points for hydrochloride and hydrobromide were determined by melting point experiment and gave sharp melting points at 251.18 °C and 205.25 °C, respectively.
I will calculate how much mephedrone is contained in 1 g of each of the listed salts.
Molar masses:
Hydrochloride - 213.71 g/mol
Hydrobromide - 258.16 g/mol
Therefore, in 1 g (rounded off) amount of mephedrone hydrochloride - 0.00468 mol, hydrobromide - 0.00387 mol.
The molar mass of the free base of mephedrone is 177.25 g/mol.
Therefore, 1 g of mephedrone hydrochloride contains 0.83 g, hydrobromide contains 0.69 g of active mephedrone. Thus, mephedrone hydrochloride and hydrobromide have the difference in the amount of active substance ~1.2 times (16.87%) less of it. The difference between effects maybe because of residual or deliberately added impurities, but not the form of the salt. In these pictures shown, crystalline structure of different mephedrone salts (left pic. - hydrochloride, right pic. - hydrobrimide).
Molar masses:
Hydrochloride - 213.71 g/mol
Hydrobromide - 258.16 g/mol
Therefore, in 1 g (rounded off) amount of mephedrone hydrochloride - 0.00468 mol, hydrobromide - 0.00387 mol.
The molar mass of the free base of mephedrone is 177.25 g/mol.
Therefore, 1 g of mephedrone hydrochloride contains 0.83 g, hydrobromide contains 0.69 g of active mephedrone. Thus, mephedrone hydrochloride and hydrobromide have the difference in the amount of active substance ~1.2 times (16.87%) less of it. The difference between effects maybe because of residual or deliberately added impurities, but not the form of the salt. In these pictures shown, crystalline structure of different mephedrone salts (left pic. - hydrochloride, right pic. - hydrobrimide).
Experiments.
You can provide some easy experiment for identification of type of your mephedrone salt. Dissolve 100 mg (100 mg is enough, but more is better) of the mephedrone sample in 7-10 ml room temperature water. Provide necessitate reaction mentioned below.
Quality reaction for chloride ions:
a) Add chloride ion solution to lead(II) acetate or lead(II) nitrate
Lead(II) chloride, white precipitate is formed when aqueous chloride solution is added to lead(II) acetate (Pb(CH3COO)2) solution or lead(II) nitrate (Pb(NO3)2) solution.
Pb(CH3COO)2(aq) + 2Cl-(aq) → PbCl2(s) + 2CH3COO- (aq)
Pb(NO3)2(aq) + 2Cl-(aq) → PbCl2(s) + 2NO3- (aq)
Lead(II) chloride (PbCl2), white precipitate is formed.
Quality reaction for chloride ions:
a) Add chloride ion solution to lead(II) acetate or lead(II) nitrate
Lead(II) chloride, white precipitate is formed when aqueous chloride solution is added to lead(II) acetate (Pb(CH3COO)2) solution or lead(II) nitrate (Pb(NO3)2) solution.
Pb(CH3COO)2(aq) + 2Cl-(aq) → PbCl2(s) + 2CH3COO- (aq)
Pb(NO3)2(aq) + 2Cl-(aq) → PbCl2(s) + 2NO3- (aq)
Lead(II) chloride (PbCl2), white precipitate is formed.
b) Add first dilute HNO3 and then AgNO3(aq). It will give AgCl white precipitate which solve in dilute NH3.
Quality reaction for chloride ions:
a) Add first dilute HNO3 and then AgNO3(aq). It will give AgBr light yellow precipitate which solve in conc. NH3.b) Add CHCl3 or CCl4 and joggle the mixture. It will give brown/orange globule.
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